Let maximum marks in the examination be \(100x\) and passing marks be \(y\)
Peter got 30% of the maximum marks, =\(30x+10=y\)-----(i)
Similarly, for Paul =\(40x-15=y\)----(ii)
Subtracting equation (i) from (ii) =\(10x=25\)
\(x=2.5\)
Substituting it in equation (ii), we get : Passing marks =\(y=85\)
The correct answer is (D) :85