Peter can cover a certain distance in 1 hour 24 minutes by covering two-thirds of the distance at 4 kmph and the rest at 5 kmph. The total distance is :
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Break down the journey into parts where the speed is constant. Use the formula Time = Distance / Speed for each part and sum the times to equal the total time given.
Step 1: Convert the total time to hours.
Total time = 1 hour 24 minutes = 1 hour + \( \frac{24}{60} \) hours = 1 hour + 0.4 hours = 1.4 hours.
Step 2: Let the total distance be \(D\) km.
Distance covered at 4 kmph = \( \frac{2}{3} D \) km.
Distance covered at 5 kmph = \( D - \frac{2}{3} D = \frac{1}{3} D \) km. Step 3: Calculate the time taken for each part of the journey.
Time taken for the first part = \( \frac{\text{Distance}}{\text{Speed}} = \frac{\frac{2}{3} D}{4} = \frac{2D}{12} = \frac{D}{6} \) hours.
Time taken for the second part = \( \frac{\text{Distance}}{\text{Speed}} = \frac{\frac{1}{3} D}{5} = \frac{D}{15} \) hours. Step 4: Set up an equation for the total time.
Total time = Time for the first part + Time for the second part
$$1.4 = \frac{D}{6} + \frac{D}{15}$$
Step 5: Solve the equation for \(D\).
Find a common denominator for 6 and 15, which is 30.
$$1.4 = \frac{5D}{30} + \frac{2D}{30}$$
$$1.4 = \frac{5D + 2D}{30}$$
$$1.4 = \frac{7D}{30}$$
Multiply both sides by 30:
$$1.4 \times 30 = 7D$$
$$42 = 7D$$
$$D = \frac{42}{7} = 6$$
The total distance is 6 km.