Question:
Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt = 78.4) then minimum molecular weight of peroxidase anhydrous enzymes is
Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt = 78.4) then minimum molecular weight of peroxidase anhydrous enzymes is
Updated On: Apr 2, 2024
- 1.568 × 10^4
- 1.568 × 10^3
- 15.68
- 2.136 × 104
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The Correct Option is A
Solution and Explanation
In peroxidase anlydrous enzyme 0.55 Se is present means, 0.5gm. Se is present in 100gm of enzyme In a molecule of enzyme one Se atom must be present hence 78.4 gm Se will be present in 0.5 100 × 78.4 = 1.568 × 104
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Concepts Used:
Molecular Mass of Polymers
It is described as the distribution rather than a specific number due to the occurrence of polymerization in such a way as to produce different chain lengths. Polymer MW is derived as follows:
\[M_{W} = \sum^{N}_{i=1} w_{i}MW_{i}.\]Where,
wi = the weight fraction of polymer chains having a molecular weight of MWi.
The MW is typically measured by light dispersing experiments. The degree of dispersing arises from the molecule size and, thus, molecular weight dispensation can be mathematically set on the total scattering created by the sample.