- Out of the 8 crew members, 3 particular members can sit only on the left side. So, they must be arranged in \( 4P3 \) ways on the left side.
- Another 2 particular members can sit only on the right side. So, they must be arranged in \( 4P2 \) ways on the right side.
For the remaining 3 crew members, we have 3 positions left on each side. These 3 remaining members can be arranged in the following ways:
- 3 members can be arranged in \( 3! \) ways on the left side.
- The remaining 3 members can be arranged in \( 3! \) ways on the right side.
Thus, the total number of arrangements is:
\[
4P3 \times 4P2 \times 3! = 1728
\]
Thus, the correct answer is 1728.