Total ways to select 2 persons from 13:
\(\binom{13}{2} = 78\)
Ways to select 2 men (no women):
\(\binom{8}{2} = 28\)
Probability of no women:
\(P(\text{no women}) = \frac{28}{78} \\= \frac{14}{39}\)
Probability of at least one woman:
\(P(\text{at least one woman}) = 1 - \frac{14}{39} \\= \frac{25}{39}\)
The probability that at least one of the selected persons will be a woman is \(\frac{25}{39}\).
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
