Total ways to select 2 persons from 13:
\(\binom{13}{2} = 78\)
Ways to select 2 men (no women):
\(\binom{8}{2} = 28\)
Probability of no women:
\(P(\text{no women}) = \frac{28}{78} \\= \frac{14}{39}\)
Probability of at least one woman:
\(P(\text{at least one woman}) = 1 - \frac{14}{39} \\= \frac{25}{39}\)
The probability that at least one of the selected persons will be a woman is \(\frac{25}{39}\).
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
