Question:

On treating 100 rnL of 0.1 M aqueous solution of the complex CrCl3.6H2O with excess of AgNO3,2.86 g of AgCl was obtained. The complex is :

Updated On: Mar 29, 2025
  • [Cr(H2O)3Cl3].3H2O
  • [Cr(H2O)4Cl2]Cl.2H2O
  • [Cr(H2O)5Cl]Cl2.H2O
  • [Cr(H2O)6Cl3]
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The Correct Option is C

Solution and Explanation

  • The problem involves the complex CrCl₃·6H₂O, which when treated with excess AgNO₃, produces 2.86 g of AgCl. The reaction indicates the displacement of chloride ions from the complex by silver ions.
  • The complex CrCl₃·6H₂O contains three chloride ions, but upon reaction with excess silver nitrate, two chloride ions are removed, and one chloride ion remains coordinated with the chromium ion in the complex.
  • This results in a complex of the form [Cr(H₂O)₅Cl]Cl₂·H₂O, where chromium is coordinated to five water molecules and one chloride ion, and there are two free chloride ions and one water molecule as part of the structure.

Thus, the correct complex is [Cr(H₂O)₅Cl]Cl₂·H₂O, making option (C) the correct answer.

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