Question:
On reduction with hydrogen, $3.6\, g$ of an oxide of metal left $3.2\, g$ of metal. If the vapour density of metal is $32$, the simplest formula of the oxide would be
On reduction with hydrogen, $3.6\, g$ of an oxide of metal left $3.2\, g$ of metal. If the vapour density of metal is $32$, the simplest formula of the oxide would be
Updated On: Jun 23, 2023
- MO
- $M_2O_3$
- $M_2O$
- $M_2O_5$
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The Correct Option is C
Solution and Explanation
Vapour density $=\frac{\text { Molecular } \quad \text { Mass }}{2}$
Molecular mass of metal $=2 \times 32=64$
given
mass of metal $=3.2 g$
no.of moles of metal $=\frac{3.2}{64}=\frac{1}{20}$
mass of oxygen $=3.6 g -3.2 g =0.4 g$
no.of moles of oxygen $=\frac{3.2}{64}=\frac{1}{40}$
The Metal oxide be in simplest form
$M \frac{1}{20} O \frac{1}{40} \Rightarrow M _{2} O$
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Concepts Used:
Some Basic Concepts of Chemistry
Chemistry is a vast subject and for understanding its significance we can take help of following points:
- Chemistry plays an important role in understanding various subjects like physics, geology and biology.
- Chemistry is a core branch of science that explains us about the various compositional properties and interaction of matter. It also helps to understand various chemical reactions.
- Chemistry is important in order to understand the behaviour of fertilizers, alkenes, acids, salts, dyes, polymers, drugs, soaps and alloys in organic and inorganic chemistry.
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Classification of Matter
There are two ways of classifying the matter:
(A) Physical Classification:
Matter can exist in three physical states:
- Solids - have definite volume and definite shape
- Liquids - have definite volume but not definite shape.
- Gases - have neither definite volume nor definite shape.
(B) Chemical Classification:
Based upon the composition, matter can be divided into two main types:
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- Mixtures are the combination of two or more elements or compounds which are not chemically combined together and may also be present in any proportion.