Question

On ozonolysis 2-methyl-2-butene gives

• A. 2 moles of CH$_3$CHO
• B. 2 moles of CH$_3$COCH$_3$
• C. CH$_3$CHO \& CH$_3$COCH$_3$
• D. CH$_3$CHO \& HCHO

Hint:

In ozonolysis, each carbon of the double bond forms a carbonyl compound—alkyl substitution decides whether it becomes an aldehyde or a ketone.

Answer 1

The Correct Option is C

Step 1: Write the structure of 2-methyl-2-butene: \[ \text{CH}_3–\text{C}(\text{CH}_3)=\text{CH}–\text{CH}_3 \]
Step 2: Ozonolysis cleaves the C=C double bond and converts each carbon of the double bond into a carbonyl compound.
Step 3: The carbon atom attached to two CH$_3$ groups forms a ketone: \[ \text{CH}_3\text{COCH}_3 \quad (\text{acetone}) \]
Step 4: The other carbon atom attached to one CH$_3$ group and one hydrogen forms an aldehyde: \[ \text{CH}_3\text{CHO} \quad (\text{acetaldehyde}) \]
Step 5: Therefore, the products of ozonolysis are CH$_3$CHO and CH$_3$COCH$_3$.