The brightness of a bulb depends on the power it dissipates, which is given by the formula: \[ P = \frac{V^2}{R} \] Where:
\( P \) is the power (brightness),
\( V \) is the voltage,
\( R \) is the resistance.
From the formula, we can see that for a constant voltage, the power (brightness) is inversely proportional to the resistance. This means that the bulb with higher resistance will glow dimmer, and the one with lower resistance will glow brighter. Therefore, the dimmer bulb has higher resistance compared to the brighter bulb.
The correct option is (B): Dim bulb