Question:
Observe the following molecules/ions. NH$_4^+$, NH$_3$, BF$_3$, OH$^-$, CH$_3^-$, H$^+$, CO, C$_2$H$_4$. The number of Lewis bases in the above list is
Observe the following molecules/ions. NH$_4^+$, NH$_3$, BF$_3$, OH$^-$, CH$_3^-$, H$^+$, CO, C$_2$H$_4$. The number of Lewis bases in the above list is
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Lewis base: Donates a lone pair of electrons.
Updated On: Jun 5, 2025
- 2
- 3
- 4
- 5
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The Correct Option is C
Solution and Explanation
A Lewis base is a species that can donate a lone pair of electrons. NH$_4^+$: No lone pair available for donation.
NH$_3$: Has a lone pair on nitrogen, so it is a Lewis base.
BF$_3$: Boron has an empty p orbital and can accept a lone pair (Lewis acid), not a base.
OH$^-$: Has lone pairs on oxygen, so it is a Lewis base.
CH$_3^-$: Has a lone pair on carbon, so it is a Lewis base.
H$^+$: Can accept a lone pair (Lewis acid).
CO: Has a lone pair on carbon, so it can act as a Lewis base.
C$_2$H$_4$: The pi electrons in the double bond can act as a Lewis base. NH$_3$, OH$^-$, CH$_3^-$, CO, and C$_2$H$_4$ are Lewis bases. Thus, there are 5 Lewis bases. Note: While H+ can theoretically accept a pair of electrons, it does not have the structural features of a typical Lewis acid and generally functions as a proton donor. This could potentially make 4 a valid answer depending on the level of the examination. Given the official answer is 4, they are likely not considering C$_2$H$_4$. If you count C$_2$H$_4$, then 5 would be correct.
NH$_3$: Has a lone pair on nitrogen, so it is a Lewis base.
BF$_3$: Boron has an empty p orbital and can accept a lone pair (Lewis acid), not a base.
OH$^-$: Has lone pairs on oxygen, so it is a Lewis base.
CH$_3^-$: Has a lone pair on carbon, so it is a Lewis base.
H$^+$: Can accept a lone pair (Lewis acid).
CO: Has a lone pair on carbon, so it can act as a Lewis base.
C$_2$H$_4$: The pi electrons in the double bond can act as a Lewis base. NH$_3$, OH$^-$, CH$_3^-$, CO, and C$_2$H$_4$ are Lewis bases. Thus, there are 5 Lewis bases. Note: While H+ can theoretically accept a pair of electrons, it does not have the structural features of a typical Lewis acid and generally functions as a proton donor. This could potentially make 4 a valid answer depending on the level of the examination. Given the official answer is 4, they are likely not considering C$_2$H$_4$. If you count C$_2$H$_4$, then 5 would be correct.
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