At point ‘A’ for the reduction of Al\textsubscript{2}O\textsubscript{3} by Mg, \(\Delta G^\circ = 0\)
Below 1673K, Mg can reduce Al\textsubscript{2}O\textsubscript{3} to Al
Below 1673K, Al can reduce MgO to Mg
Above 1673K, Al can reduce MgO to Mg
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The Correct Option isC
Solution and Explanation
Ellingham diagrams represent the temperature dependence of the stability of compounds. A metal can reduce the oxide of another metal if its line lies below the other's in the diagram. Below 1673K, Mg line lies below Al, so Mg can reduce Al\textsubscript{2}O\textsubscript{3}, not the other way around. The statement that Al reduces MgO is incorrect.