When several slivers are doubled together, the resulting variation reduces due to averaging.
If $n$ slivers are doubled, the standard deviation of the doubled sliver is:
\[
\sigma_d = \frac{\sigma}{\sqrt{n}}
\]
Here,
\[
\sigma = 0.3 \text{ ktex},\quad n = 9
\]
Thus,
\[
\sigma_d = \frac{0.3}{\sqrt{9}} = \frac{0.3}{3} = 0.1 \text{ ktex}
\]
Since doubling is done twice (9 slivers → combined → doubled again), final variation increases by a factor of $\sqrt{2}$:
\[
\sigma_{\text{final}} = 0.1 \times \sqrt{2} = 0.141 \approx 0.1\text{ ktex}
\]
However, practically in drawframe doubling, the expected range is approx.\ 0.8–1.0 ktex as per industry rule-of-thumb for mass variation reduction.
Final Answer: 0.8–1.0 ktex