Step 1: Formulate the cost equations for each service.
Let \(C_p\) be the total cost at the nearby print shop and \(C_o\) be the total cost at the online service.
Cost at Print Shop: \( C_p = 200 \times m \)
Cost at Online Service: \( C_o = (200 \times n) + 50 \)
Step 2: Use the information about the savings to create an equation.
The savings from choosing the online service is the difference between the print shop cost and the online service cost.
\[ \text{Savings} = C_p - C_o \]
\[ 290 = (200m) - ((200n) + 50) \]
Step 3: Solve the equation to find the relationship between m and n.
\[ 290 = 200m - 200n - 50 \]
\[ 290 + 50 = 200m - 200n \]
\[ 340 = 200(m - n) \]
\[ m - n = \frac{340}{200} = \frac{34}{20} = \frac{17}{10} \]
\[ m - n = 1.7 \]
Step 4: Test the given values to find a pair (m, n) that satisfies the equation.
The list of possible values is \{2.2, 0.8, 0.5, 1.8, 0.3, 0.2\}. We need to find two values from this list, one for m and one for n, such that their difference is 1.7.
Let's test the possible values for m:
If \(m = 2.2\), then \(n = m - 1.7 = 2.2 - 1.7 = 0.5\). The value 0.5 is available in the list.
If \(m = 1.8\), then \(n = 1.8 - 1.7 = 0.1\). The value 0.1 is not available in the list.
Other values for m are smaller than 1.7, which would result in a negative value for n, which is not sensible for a price.
Step 5: Final Answer
The only consistent pair of values is \(m = 2.2\) and \(n = 0.5\).