Question:
\Mien borax is heated dining borax bead test along with CoO (Cobalt Oxide) on a loop of platinum (Pt) wire, it swells up and produces a blue colored bead. Which of the following compounds is responsible for the blue color?
\Mien borax is heated dining borax bead test along with CoO (Cobalt Oxide) on a loop of platinum (Pt) wire, it swells up and produces a blue colored bead. Which of the following compounds is responsible for the blue color?
Updated On: Mar 11, 2025
- $\ce{Pt(BO_2)_4}$
- $\ce{CO(BO_2)_3}$
- $\ce{CO(BO_2)_2}$
- $\ce{NaBO_2}$
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The Correct Option is C
Solution and Explanation
Answer (c) $ {CO(BO_2)_2}$
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family