Question:

Maximum shear stress in a thin cylindrical shell subjected to internal pressure \( p \) is

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In thin cylinders, maximum shear stress occurs midway between hoop and longitudinal stresses.
Updated On: Feb 9, 2026
  • \( \dfrac{pd}{t} \)
  • \( \dfrac{pd}{2t} \)
  • \( \dfrac{pd}{4t} \)
  • \( \dfrac{pd}{8t} \)
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The Correct Option is C

Solution and Explanation

Step 1: Identifying principal stresses.
In a thin cylindrical shell subjected to internal pressure, the two principal stresses are:
Hoop stress: \[ \sigma_h = \frac{pd}{2t} \] Longitudinal stress: \[ \sigma_l = \frac{pd}{4t} \]
Step 2: Formula for maximum shear stress.
Maximum shear stress is given by: \[ \tau_{\max} = \frac{\sigma_h - \sigma_l}{2} \]
Step 3: Substituting values.
\[ \tau_{\max} = \frac{\frac{pd}{2t} - \frac{pd}{4t}}{2} \] \[ \tau_{\max} = \frac{pd}{4t} \]
Step 4: Conclusion.
The maximum shear stress in the cylindrical shell is \( \dfrac{pd}{4t} \).
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