Question

Match the List-I with List-II in the following :

List-I		List-II
1.	Caprolactum	(a)
2.	Vinyl chloride	(b)
3.	Styrene	(c)
4.	Propene	(d)

• A. 1-c, 2-d, 3-a, 4-b
• B. 1-a, 2-d, 3-c, 4-b
• C. 1-d, 2-c, 3-a, 4-b
• D. 1-d, 2-c, 3-b, 4-a

Answer 1

The Correct Option is D

1. Caprolactam:

Caprolactam is a cyclic amide (lactam) that undergoes polymerization to form nylon 6. Nylon 6 is a synthetic polymer, known as polycaprolactam, and is used widely in textiles and plastics.

2. Vinyl chloride:

Vinyl chloride is a monomer that polymerizes to form polyvinyl chloride (PVC). PVC is one of the most widely used synthetic polymers, commonly found in pipes, flooring, and electrical insulation.

3. Styrene:

Styrene is a monomer that undergoes polymerization to form polystyrene. Polystyrene is used in a variety of applications, including packaging, insulation, and disposable cutlery.

4. Propene (propylene):

Propene, also known as propylene, is a monomer that polymerizes to form polypropylene. Polypropylene is a versatile polymer used in packaging, textiles, automotive parts, and many other applications.

Conclusion: 

Now, let's match each monomer with its corresponding polymer:

• Caprolactam forms nylon 6 (polycaprolactam) – This corresponds to 1 – d.
• Vinyl chloride forms polyvinyl chloride (PVC) – This corresponds to 2 – c.
• Styrene forms polystyrene – This corresponds to 3 – b.
• Propene (propylene) forms polypropylene – This corresponds to 4 – a.

The correct matching is Option B: 1 – d, 2 – c, 3 – b, 4 – a.