Match the following molecules with their bond angles:
List-I (Molecule) | List-II (Bond angle) | ||
---|---|---|---|
A) \(\mathrm{NH}_3\) | I) 102.2° | ||
B) \(\mathrm{O}_3\) | II) 107.8° | ||
C) \(\mathrm{S}_6\) | III) 93.6° | ||
D) \(\mathrm{PH}_3\) | IV) 117° |
- \({NH}_3\): 107.8°
- \({O}_3\): 117°
- \({S}_6\): 102.2° (approximate)
- \({PH}_3\): 93.6°
In the below reaction, geometry of BCl3, X respectively are \(\text{BC}_{3} + \text{NH}_{3} \rightarrow X\)