Question

Match the following materials with their corresponding bonding types.

• A. P - 4;\; Q - 2;\; R - 3;\; S - 1
• B. P - 3;\; Q - 4;\; R - 2;\; S - 1
• C. P - 3;\; Q - 2;\; R - 1;\; S - 4
• D. P - 3;\; Q - 1;\; R - 4;\; S - 2

Hint:

Metallic elements form metallic bonds; compounds with large electronegativity difference are ionic; semiconductors like ZnS show covalent bonding; complex oxides often show mixed bonding.

Answer 1

The Correct Option is C

P: Cu\(_{0.5}\)Al\(_{0.5}\) is an alloy containing Cu and Al, both metallic elements. Alloys show metallic bonding. Hence P → 3.
Q: ZnS is a classic example of sphalerite or zinc blende structure, which is a covalently bonded semiconductor. Thus Q → 2.
R: Na\(_2\)O contains Na and O with a strong electropositive–electronegative difference, forming a fully ionic compound. So R → 1.
S: Li\(_4\)SiO\(_4\) contains metals (Li) and a covalently bonded anion group (SiO\(_4\) tetrahedron). Such materials show mixed ionic–covalent bonding. Therefore S → 4.
Thus the correct matching is:
P – 3,\; Q – 2,\; R – 1,\; S – 4
Which corresponds to option (C).