Match List I with List II LIST I LIST II A. The maximum value of the function $f(x)=25x-\frac{5x^2}{2}+7$ in [-1,6] is I. 24 B. The minimum value of the function $f(x)=2x^3-15x^2+36x+1$ in [1,5] is II. $\frac{1}{16}$ C. The maximum value of the function $f(x)=\frac{x}{2}-x^2$ in [0,1] is III. $\frac{139}{2}$ D. The least value of the function $f(x)=\frac{9}{x+3}+x$ in [-7,1], $x\ne-3$ is IV. $-\frac{37}{4}$ Choose the correct answer from the options given below:

Question

Match List I with List II LIST I LIST II A. The maximum value of the function $f(x)=25x-\frac{5x^2}{2}+7$ in [-1,6] is I. 24 B. The minimum value of the function $f(x)=2x^3-15x^2+36x+1$  in [1,5] is II. $\frac{1}{16}$ C. The maximum value of the function $f(x)=\frac{x}{2}-x^2$  in [0,1] is III. $\frac{139}{2}$ D. The least value of the function $f(x)=\frac{9}{x+3}+x$  in [-7,1],  $x\ne-3$  is IV. $-\frac{37}{4}$ Choose the correct answer from the options given below:

cdquestions Admin · Accepted Answer

The correct option is (D): A-III, B-I, С-II, D-IV

Answer

А-I, В-III, C-II, D-IV

Answer

A-III, B-I, С-IV, D-II

Answer

A-II, B-IV, С-III, D-I

Answer

A-III, B-I, С-II, D-IV

The Correct Option is D

Solution and Explanation

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LIST I		LIST II
A.	The maximum value of the function $f(x)=25x-\frac{5x^2}{2}+7$ in [-1,6] is	I.	24
B.	The minimum value of the function $f(x)=2x^3-15x^2+36x+1$ in [1,5] is	II.	$\frac{1}{16}$
C.	The maximum value of the function $f(x)=\frac{x}{2}-x^2$ in [0,1] is	III.	$\frac{139}{2}$
D.	The least value of the function $f(x)=\frac{9}{x+3}+x$ in [-7,1], $x\ne-3$ is	IV.	$-\frac{37}{4}$