Question:
Match List I with List II
List-I
(Complex)
List-II
(Type of isomerism)
(A) [Co(NH3)5(NO2)]Cl2 (I) Solvate isomerism (B) [Co(NH3)5(SO4)]Br (II) Linkage isomerism (C) [Co(NH3)6] [Cr(CN)6] (III) Ionization isomerism (D) [Co(H2O)6]Cl3 (IV) Coordination isomerism
Choose the correct answer from the options given below:
Match List I with List II
Choose the correct answer from the options given below:
List-I | List-II | ||
| (A) | [Co(NH3)5(NO2)]Cl2 | (I) | Solvate isomerism |
| (B) | [Co(NH3)5(SO4)]Br | (II) | Linkage isomerism |
| (C) | [Co(NH3)6] [Cr(CN)6] | (III) | Ionization isomerism |
| (D) | [Co(H2O)6]Cl3 | (IV) | Coordination isomerism |
Choose the correct answer from the options given below:
Updated On: Dec 4, 2024
- A-II, B-III, C-IV, D-I
- A-I, B-III, C-IV, D-II
- A-I, B-IV, C-III, D-II
- A-II, B-IV, C-III, D-I
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Verified By Collegedunia
The Correct Option is A
Solution and Explanation
- Complex A exhibits ionization isomerism because $NO_2^-$ can ionize.
- Complex B shows solvate isomerism due to $SO_4^{2-}$ exchange with water molecules.
- Complex C shows coordination isomerism between the two metal centers.
- Complex D shows linkage isomerism because $Cl^-$ can bind in multiple ways.
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