Question:

Match List-I with List-II:
List-IList-II
(A) Lyman(i) n = 2, 3, 4, ...
(B) Balmer(ii) n = 3, 4, 5, ...
(C) Paschen(iii) n = 4, 5, 6, ...
(D) Bracket(iv) n = 5, 6, 7, ...
Choose the correct answer from the options given below:

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Lyman transitions end in n=1, emitting UV radiation; Balmer transitions end in n=2 and emit visible light; Paschen ends in n=3 with IR radiation, and Bracket series is in far IR with n=4.
Updated On: Jan 2, 2025
  • (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
  • (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
  • (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
  • (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
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The Correct Option is A

Solution and Explanation

Hydrogen spectral series and their transitions:
• Lyman series ends at n=1 and involves levels of n=2,3,4 etc.
• Balmer series ends at n=2 and involves energy levels of n=3,4,5 etc
• Paschen series ends at n=3 and involves energy levels of n =4,5,6 etc
• Bracket series ends at n=4 and involves energy levels of n=5,6,7 etc
The correct matching is: (A) - (i), (B) - (ii), (C) - (iii), (D) - (iv).

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