Question

Match List - I with List - II.

List - I		List - II
(a)		(i)	Hell-VolhardZelinsky reaction
(b)		(ii)	Gattermann-Koch reaction
(c)		(iii)	Haloform reaction
(d)		(iv)	Esterification

Choose the correct answer from the options given below.

• A. (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
• B. (a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)
• C. (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
• D. (a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)

Answer 1

The Correct Option is A

To solve this question, we need to match the reactions shown in List - I with their correct names from List - II.

1. (a) The reaction shown in image (a) is:

   

   This reaction is the Gattermann-Koch reaction. It involves the formation of benzaldehyde from benzene using carbon monoxide and hydrogen chloride in the presence of a catalyst like anhydrous AlCl₃.
2. (b) The reaction in image (b) is:

   

   This is the Haloform reaction, where methyl ketones react with halogen in the presence of a base to form carboxylic acid and haloform (like chloroform).
3. (c) The reaction in image (c) is:

   

   This is the process of Esterification. It is the reaction between an alcohol and a carboxylic acid to form an ester and water, typically in the presence of an acid catalyst.
4. (d) The reaction in image (d) is:

   

   This represents the Hell-Volhard-Zelinsky reaction, where carboxylic acids are halogenated at the alpha position using phosphorus tribromide and bromine.

Therefore, the correct matching is:

• (a)-(ii): Gattermann-Koch reaction
• (b)-(iii): Haloform reaction
• (c)-(iv): Esterification
• (d)-(i): Hell-Volhard-Zelinsky reaction

Thus, the correct option is (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i).