List - I Type of Inheritance | List – II Example | ||
A. | Incomplete dominance | i. | Blood groups in human |
B. | Co-dominance | ii. | Flower colour in Antirrhinum |
C. | Pleiotropy | iii. | Skin colour in human |
D. | Polygenic inheritance | iv. | Phenylketonuria |
A. Incomplete dominance - II. Flower colour in Antirrhinum: In incomplete dominance, the heterozygote shows an intermediate phenotype (e.g., pink flowers from red and white parents).
B. Co-dominance - I. Blood groups in humans: In co-dominance, both alleles are expressed in the heterozygote (e.g., AB blood type).
C. Pleiotropy - IV. Phenylketonuria: Pleiotropy refers to a single gene affecting multiple traits or symptoms.
D. Polygenic inheritance - III. Skin colour in humans: Polygenic inheritance involves multiple genes contributing to a single trait. Skin color is a classic example of polygenic inheritance.
Therefore, the correct matches are: A-II, B-I, C-IV, and D-III. This corresponds to option (2).
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |
Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : The potential (V) at any axial point, at 2 m distance(r) from the centre of the dipole of dipole moment vector
\(\vec{P}\) of magnitude, 4 × 10-6 C m, is ± 9 × 103 V.
(Take \(\frac{1}{4\pi\epsilon_0}=9\times10^9\) SI units)
Reason R : \(V=±\frac{2P}{4\pi \epsilon_0r^2}\), where r is the distance of any axial point, situated at 2 m from the centre of the dipole.
In the light of the above statements, choose the correct answer from the options given below :