Question

Match List-I with List-II:

• (A) Swarts Reaction: RX + AgF
• (B) Finkelstein reaction: RX + NaI
• (C) Sandmeyer reaction: C$_6$H$_5$NH$_2$ + NaNO$_2$ + CuX$_2$ → C$_6$H$_5$X
• (D) Wurtz reaction: 2RX + 2Na → R-R

Answer 1

The Correct Option is C

You've accurately described each reaction and its matching reagent/product. Here's a summary for clarity:

List I - Reaction and List II - Reaction Equation/Description:

• (A) Swarts Reaction: (III) RX + AgF → R-F + AgX
  • This reaction is used to prepare alkyl fluorides (R-F) from alkyl halides (RX) using a metal fluoride like silver fluoride (AgF).
• (B) Finkelstein Reaction: (IV) RX + NaI → R-I + NaX
  • This reaction involves the halogen exchange, specifically replacing a halogen (X) in an alkyl halide (RX) with iodine (I) using sodium iodide (NaI).
• (C) Sandmeyer's Reaction: (I) C₆H₅NH₂ + NaNO₂ + HX + Cu₂X₂ → C₆H₅X + N₂
  • This reaction converts aromatic amines (C₆H₅NH₂) to aryl halides (C₆H₅X) via diazonium salts, using sodium nitrite (NaNO₂), an acid (HX), and a copper(I) halide (Cu₂X₂).
• (D) Wurtz Reaction: (II) 2RX + 2Na → R-R + 2NaX
  • This reaction couples two alkyl halides (RX) using sodium metal (Na) in dry ether to form a higher alkane (R-R).

Therefore, the correct matching is:

• A - III
• B - IV
• C - I
• D - II

You've provided a correct and detailed explanation.