Question:
Match hypersensitivity types in Group I with their corresponding condition in Group II.
\[\begin{array}{c c} \textbf{Group I} & \textbf{Group II} \\ \text{P. Type I} & \text{1. Erythroblastosis fetalis} \\ \text{Q. Type II} & \text{2. Host reaction to bee venom} \\ \text{R. Type III} & \text{3. Systemic lupus erythematosus} \\ \text{S. Type IV} & \text{4. Tuberculin reaction} \\ \end{array}\]
Match hypersensitivity types in Group I with their corresponding condition in Group II.
\[\begin{array}{c c} \textbf{Group I} & \textbf{Group II} \\ \text{P. Type I} & \text{1. Erythroblastosis fetalis} \\ \text{Q. Type II} & \text{2. Host reaction to bee venom} \\ \text{R. Type III} & \text{3. Systemic lupus erythematosus} \\ \text{S. Type IV} & \text{4. Tuberculin reaction} \\ \end{array}\]
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Remember: I–Allergy, II–Cytotoxic, III–Immune complex, IV–Delayed.
Updated On: Jan 2, 2026
- P-2, Q-3, R-1, S-4
- P-3, Q-1, R-4, S-2
- P-2, Q-3, R-4, S-1
- P-2, Q-1, R-3, S-4
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The Correct Option is D
Solution and Explanation
Type I hypersensitivity = immediate allergy → bee venom reaction (2)
Type II = antibody-mediated cytotoxicity → erythroblastosis fetalis (1)
Type III = immune complex disease → SLE (3)
Type IV = delayed-type hypersensitivity → tuberculin reaction (4)
[4pt] Thus, the correct match is P-2, Q-1, R-3, S-4.
Type II = antibody-mediated cytotoxicity → erythroblastosis fetalis (1)
Type III = immune complex disease → SLE (3)
Type IV = delayed-type hypersensitivity → tuberculin reaction (4)
[4pt] Thus, the correct match is P-2, Q-1, R-3, S-4.
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