The induced e.m.f \( \mathcal{E} \) is given by Faraday's law of induction:
\[
\mathcal{E} = -N \frac{\Delta \Phi}{\Delta t}
\]
Where:
- \( N = 20 \) (number of turns)
- \( \Delta \Phi = 0.3 \, \text{weber} \)
- \( \Delta t = 1 \, \text{second} \)
Now, calculate the induced e.m.f:
\[
\mathcal{E} = -20 \times \frac{0.3}{1} = -6 \, \text{V}
\]
Thus, the induced e.m.f is 6 V.