Question:

Magnetic field on the axis of a short bar magnet of magnetic moment \( M \), at a distance \( x \) from its centre is:

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For magnetic fields due to a bar magnet, the field on the axis is proportional to \( \frac{1}{x^3} \), and the formula incorporates the magnetic moment.
Updated On: Mar 12, 2025
  • \( \frac{\mu_0 M}{2 \pi x^3} \)
  • \( \frac{\mu_0 M}{4 \pi x^3} \)
  • \( \frac{2 \mu_0 M}{\pi x^3} \)
  • \( \frac{4 \mu_0 M}{\pi x^3} \)
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The Correct Option is A

Solution and Explanation

The magnetic field \( B \) at a point on the axis of a bar magnet is given by the formula: \[ B = \frac{\mu_0 M}{2 \pi x^3} \] where:
- \( \mu_0 \) is the permeability of free space,
- \( M \) is the magnetic moment of the bar magnet,
- \( x \) is the distance from the center of the magnet.
Thus, the magnetic field is directly proportional to the magnetic moment and inversely proportional to the cube of the distance from the magnet.
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