Question:
Magnesium is burnt in air to form $A$ and $B$. When $B$ is hydrolysed, $C$ and $D$ are formed. $D$ is the reactant in the manufacture of nitric acid by Ostwald's process. What is $C$
Magnesium is burnt in air to form $A$ and $B$. When $B$ is hydrolysed, $C$ and $D$ are formed. $D$ is the reactant in the manufacture of nitric acid by Ostwald's process. What is $C$
Updated On: Aug 15, 2022
- $\ce{NH_3}$
- $\ce{Mg(OH)_2}$
- $MgO$
- $NO$
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The Correct Option is B
Solution and Explanation
When magnesium is burnt in air, it forms two products $(A$ and $B)$. The, compound '$A$' is magnesium oxide and compound ' $B$' is traces of magnesium nitride (formed as a result of reaction between magnesium and molecular nitrogen).
Now, on hydrolysis of magnesium nitride $(B)$, it forms ammonia and magnesium hydroxide.
Since, '$D$' is the reactant in the manufacture of nitric acid by Ostwald's process. Thus, compound '$D$' is $NH _{3}$ and compound ' $C$' is $Mg ( OH )_{2}$.
The respective reactions for the following information are as follows:
$2Mg(s) + O_2(g) {->[\Delta]} \underset{'A'}{2MgO(s)}$ (magnesium oxide)
$3Mg(s) + N_2(g) \rightarrow \underset{'B'}{Mg_3N_2(s)}$ (magnesium nitride)
$Mg_3N_2(s) + 6H_2O(l) \rightarrow \underset{C}{3Mg(OH)_2(s) }+ 2NH_3(g)$ (magnesium hydroxide)
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P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
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