Question:
log \([\frac{x+y}{2}]=\frac{1}{2}\) (log x+log y) the value of \(\frac{x}{y}+\frac{y}{x}\) is
log \([\frac{x+y}{2}]=\frac{1}{2}\) (log x+log y) the value of \(\frac{x}{y}+\frac{y}{x}\) is
Updated On: Feb 18, 2024
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Correct Answer: 2
Solution and Explanation
The correct answer is 2.
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