Step 1: Understand valence electrons of Xenon.
Xenon (Xe) has 8 valence electrons.
While forming compounds, some electrons are used in bonding and remaining electrons form lone pairs.
Step 2: Check common Xenon compounds.
(i) $XeF_2$
Electron pairs around Xe = 5 (2 bonding + 3 lone pairs).
Hence, 3 lone pairs are present.
(ii) $XeF_4$
Electron pairs around Xe = 6 (4 bonding + 2 lone pairs).
Hence, 2 lone pairs are present.
(iii) $XeF_6$
Electron pairs around Xe = 7 (6 bonding + 1 lone pair).
Hence, 1 lone pair is present.
(iv) $XeO_3$
Total electron domains = 4 (3 bonding + 1 lone pair).
Hence, 1 lone pair is present.
(v) $XeOF_4$
Total electron domains = 6 (5 bonding + 1 lone pair).
Hence, 1 lone pair is present.
Step 3: Final Answer.
Compounds of Xenon having one lone pair are:
\[
\boxed{XeF_6,\; XeO_3,\; XeOF_4}.
\]