Step 1: Convert each binary number to decimal using 2's complement.
- For \( 11001 \) in 2's complement:
- The first bit is 1, so it is negative.
- To find the decimal, take the 2's complement of \( 11001 \): \[ 11001 \quad {(invert)} \quad 00110 \quad {(add 1)} \quad 00111 = 7. \] Thus, \( 11001 \) corresponds to \( -7 \). - For \( 1001 \) in 2's complement:
- The first bit is 1, so it is negative.
- To find the decimal, take the 2's complement of \( 1001 \): \[ 1001 \quad {(invert)} \quad 0110 \quad {(add 1)} \quad 0111 = 7. \] Thus, \( 1001 \) corresponds to \( -7 \). - For \( 111001 \) in 2's complement:
- The first bit is 1, so it is negative.
- To find the decimal, take the 2's complement of \( 111001 \): \[ 111001 \quad {(invert)} \quad 000110 \quad {(add 1)} \quad 000111 = 7. \] Thus, \( 111001 \) corresponds to \( -7 \).
Step 2: Conclusion. Thus, the given binary numbers correspond to \( -7, -7, { and } -7 \) in decimal. \[ \boxed{-7, -7, { and } -7}. \]
The Boolean expression for the following truth table is:
Consider the program below which uses six temporary variables a, b, c, d, e and f.
a = 10
b = 20
c = 30
d = a + c
e = b + d
f = c + c
b = c + e
e = b + f
d = 5 + e
return d + f
Assuming that all the above operations take their operands from registers, the minimum number of registers needed to execute this program without spilling is:
Five friends A, B, C, D, and E are sitting in a row facing north, but not necessarily in the same order:
B is to the immediate left of C
E is not at any of the ends
D is to the right of E but not next to C
A is at one of the ends
Who is sitting in the middle?