Let f : R $\rightarrow$ R be function defined by f(x) = sin (2x -3), then f is
Updated On: Oct 3, 2024
injective
surjective
bijective
None of these
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The Correct Option isD
Solution and Explanation
Since sin (2x - 3) is a periodic function with period $\pi$, therefore f is not injective. Also, f is not surjective as its range [-1, 1] is a proper subset of its co-domain R.