Let \(f:R\rightarrow R\) be defined by \(f(x) = \begin{cases} k-2x,x\le-1\\ 2x+3,x\gt-1 \end{cases}\). If f(x) has a local minimum at x=- 1, then a possible value of k is
- 0
- \(-\frac{1}{2}\)
- -1
- 1
The Correct Option is C
Solution and Explanation
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