Question:

Let f:RRf:R\rightarrow R be defined by f(x)={k2x,x12x+3,x>1 f(x) = \begin{cases} k-2x,x\le-1\\ 2x+3,x\gt-1   \end{cases}. If f(x) has a local minimum at x=- 1, then a possible value of k is

Updated On: Oct 4, 2024
  • 0
  • 12-\frac{1}{2}
  • -1
  • 1
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The Correct Option is C

Solution and Explanation

The correct option is (C): -1
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