Question:

Let \(f:R\rightarrow R\) be defined by \(f(x) = \begin{cases} k-2x,x\le-1\\ 2x+3,x\gt-1   \end{cases}\). If f(x) has a local minimum at x=- 1, then a possible value of k is

Updated On: Oct 4, 2024
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  • \(-\frac{1}{2}\)
  • -1
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The Correct Option is C

Solution and Explanation

The correct option is (C): -1
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