Let a causal LTI system be governed by the following differential equation
\[
y(t) + \frac{1}{4} \frac{dy}{dt} = 2x(t),
\]
where \( x(t) \) and \( y(t) \) are the input and output respectively. Its impulse response is
Show Hint
For an LTI system described by a first-order differential equation, the impulse response is found by taking the inverse Laplace transform of the transfer function.
Step 1: Understanding the System.
This is a first-order linear differential equation. To find the impulse response \( h(t) \), we need to solve for the system's response when the input is a Dirac delta function \( \delta(t) \).
Step 2: Solving the Differential Equation.
To find the impulse response, we first take the Laplace transform of the given equation. The Laplace transform of the equation is:
\[
Y(s) + \frac{1}{4}sY(s) = 2X(s)
\]
Solving for the transfer function \( H(s) = \frac{Y(s)}{X(s)} \), we get:
\[
H(s) = \frac{2}{s + \frac{1}{4}}
\]
Taking the inverse Laplace transform of \( H(s) \), we get the impulse response:
\[
h(t) = 2e^{-\frac{1}{4}t}u(t)
\]
Step 3: Conclusion.
The correct answer is (A) \( 2e^{-\frac{1}{4}t}u(t) \), which is the impulse response of the system.
Was this answer helpful?
0
0
Top Questions on Linear time invariant and causal systems