Question:

Let A be the problem of finding a Hamiltonian cycle in a graph G = (V, E) with |V| divisible by 3, and B be the problem of determining if a Hamiltonian cycle exists in such graphs. Which one of the following is true?

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Modifying problem constraints (like divisibility) does not necessarily reduce complexity if the core problem remains NP-hard.
Updated On: Dec 29, 2024
  • Both A and B are NP-hard
  • A is NP-hard but B is not
  • B is NP-hard but A is not
  • Neither A nor B is NP-hard
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The Correct Option is A

Solution and Explanation

- Finding a Hamiltonian cycle is a well-known NP-complete problem. Restricting the graph G to have |V| divisible by 3 does not reduce its computational complexity. - Determining if such a cycle exists in graphs is also NP-hard, as it involves solving the same Hamiltonian cycle problem. - Therefore, both A and B are NP-hard.
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