Question

$K_{\alpha} $ and $K_{\beta} x-$ rays are emitted when there is a transition of electron between the levels

• A. n = 2 to n = 1 and n = 3 to n = 1 respectively
• B. n = 2 to n = 1 and n = 3 to n = 2 respectively
• C. n = 3 to n = 2 and n = 4 to n = 2 respectively
• D. n = 3 to n = 2 and n = 4 to n = 3 respectively

Answer 1

The Correct Option is A

When the colliding electron remove an electron from innermost $K$ - shell (corresponding to $n=1$ ) of atom and electron from some higher shell jumps to $K$ - shell to fill up this vacancy, characteristic $X$ - ray of $K$ - series are obtained

$\therefore K_{\alpha}$ and $K_{\beta} X$-rays are emitted when there is transition of electron between the levels $n=2$ to $n=1$ and $n=3$ to $n=1$ respectively.

Answer 2

The distribution of electrons within an atomic subshell is described by the electron configuration.

Atomic electron configurations adhere to a standard nomenclature whereby all electrons that comprise atomic subshells are arranged in a sequence with their total number of electrons indicated by a superscript.

For instance, sodium's electron configuration is 1s² 2s² 2p⁶ 3s¹.

The four quantum numbers (n) that make up the definition of an electron in an atom, the most significant of which specifies the primary energy level known as a shell. 

The quantum numbers of the last orbital filled are used to identify an element's position in the periodic table.

The usual notation of electron configuration may be rather lengthy for big atomic numbers. In certain circumstances, an abridged or condensed notation may be employed in place of the conventional notation. 

In the shortened notation, the sequence of fully filled subshells that corresponds to a noble gas's electronic configuration is substituted by the gas's symbol enclosed in square brackets.

Because of this, sodium's electron configuration is [Ne]3s¹ (in contrast to neon, whose electron configuration is 1s² 2s² 2p⁶, or [He]2s² 2p⁶).