Selling price = Rs \(13500\)
Loss % = \(20\%\)
Let the cost price be \(x\).
Loss = \(20\%\) of \(x\)
Cost price - Loss = Selling price
\(x-\frac{20}{100}\times x=13500\)
\(x-\frac{1}{5}x=13500\)
\(\frac{4}{5}x=13500\)
\(x= 13500\times\frac{5}{4}\)
= \(16875\)
Therefore, she bought it for Rs \(16875\).
LIST I | LIST II | ||
A. | Secular movements | I. | Price increase before Deepavali |
B. | Seasonal variations | II. | Increase in price of gold during a major war |
C. | Cyclic variations | III. | Long term trends |
D. | Irregular variations | IV. | Recurring rise and decline in production |
Write equations for the following statements:
(i) The sum of numbers x and 4 is 9.
(ii) 2 subtracted from y is 8.
(iii) Ten times a is 70.
(iv) The number b divided by 5 gives 6.
(v) Three-fourth of t is 15.
(vi) Seven times m plus 7 gets you 77.
(vii) One-fourth of a number x minus 4 gives 4.
(viii) If you take away 6 from 6 times y, you get 60.
(ix) If you add 3 to one-third of z, you get 30