Step 1: Understanding the Concept:
This is a data sufficiency question involving inequalities. We need to determine if the product \(xy\) is definitively greater than 24. We must test if the given statements constrain \(x\) and \(y\) in such a way that \(xy > 24\) is always true or always false.
Step 2: Key Formula or Approach:
We will analyze the inequalities provided in each statement. A statement is sufficient if it leads to a definite "Yes" or a definite "No" answer. If we can find examples that give both "Yes" and "No" answers, the statement is not sufficient.
Step 3: Detailed Explanation:
Analyzing Statement (1): y - 2 $<$ x
This inequality can be rewritten as \(y < x + 2\).
Let's test some cases:
- Case 1 (Answer "Yes"): If \(x=10\), then \(y < 12\). Let's choose \(y=10\). Then \(xy = 100\), and \(100 > 24\).
- Case 2 (Answer "No"): If \(x=4\), then \(y < 6\). Let's choose \(y=5\). Then \(xy = 20\), and \(20\) is not greater than 24.
Since we can get both "Yes" and "No" answers, Statement (1) ALONE is not sufficient.
Analyzing Statement (2): 2y $>$ x + 8
This inequality can be rewritten as \(y > \frac{x}{2} + 4\).
Let's test some cases:
- Case 1 (Answer "Yes"): If \(x=10\), then \(y > \frac{10}{2} + 4\), so \(y > 9\). Let's choose \(y=10\). Then \(xy = 100\), and \(100 > 24\).
- Case 2 (Answer "No"): If \(x=2\), then \(y > \frac{2}{2} + 4\), so \(y > 5\). Let's choose \(y=6\). Then \(xy = 12\), and \(12\) is not greater than 24.
Since we can get both "Yes" and "No" answers, Statement (2) ALONE is not sufficient.
Analyzing Statements (1) and (2) Together:
We have a system of two inequalities:
1. \(y < x + 2\)
2. \(y > \frac{x}{2} + 4\)
Combining them, we get:
\[ \frac{x}{2} + 4 < y < x + 2 \]
For this range of \(y\) to exist, the lower bound must be less than the upper bound:
\[ \frac{x}{2} + 4 < x + 2 \]
Subtract \(\frac{x}{2}\) from both sides:
\[ 4 < \frac{x}{2} + 2 \]
Subtract 2 from both sides:
\[ 2 < \frac{x}{2} \]
Multiply by 2:
\[ 4 < x \]
So, a necessary condition for both statements to hold is that \(x\) must be greater than 4. (Assuming x and y are positive, which is standard unless specified).
Now, let's look at the product \(xy\). We can use the inequality for \(y\):
\[ xy > x \left(\frac{x}{2} + 4\right) \]
\[ xy > \frac{x^2}{2} + 4x \]
Let's analyze the expression \(\frac{x^2}{2} + 4x\). We know that \(x > 4\). Let's see what the minimum value of this expression is for \(x > 4\).
Let \(f(x) = \frac{x^2}{2} + 4x\). Since this is an upward-opening parabola, its value increases for \(x > -4\). As our domain is \(x > 4\), the expression will be minimized as \(x\) approaches 4 from the right.
Let's evaluate the expression at \(x=4\):
\[ f(4) = \frac{4^2}{2} + 4(4) = \frac{16}{2} + 16 = 8 + 16 = 24 \]
Since we know that \(x > 4\), it must be true that \(\frac{x^2}{2} + 4x > 24\).
Therefore, we have:
\[ xy > \frac{x^2}{2} + 4x > 24 \]
This proves that \(xy\) must always be greater than 24. The answer to the question is a definite "Yes".
Therefore, both statements TOGETHER are sufficient.
Step 4: Final Answer:
Neither statement is sufficient on its own, but when combined, they provide enough information to definitively answer the question. The correct option is (B).
John has 50 for soda and he must buy both diet and regular sodas. His total order must have at exactly two times as many cans of diet soda as cans of regular soda. What is the greatest number of cans of diet soda John can buy if regular soda is 0.50 per can and diet soda is $0.75 per can?
In a certain batch of guests in a museum, there are 50 guests; each guest buys either a 40 ticket or a 60 ticket, with at least one guest of each ticket type. The average (arithmetic mean) value of ticket-receipts from the batch is more than 50. If the average value of ticket-receipts is to be reduced to less than 50 by including few new guests with $40 tickets, what could definitely NOT be the number of new guests with $40 tickets that could be included?
Indicate all such numbers.
[Note: Select one or more answer choices]
In a certain batch of guests in a museum, there are 50 guests; each guest buys either a 40 ticket or a 60 ticket, with at least one guest of each ticket type. The average (arithmetic mean) value of ticket-receipts from the batch is more than 50. If the average value of ticket-receipts is to be reduced to less than 50 by including few new guests with 40 tickets, what could definitely NOT be the number of new guests with $40 tickets that could be included?
Indicate all such numbers.
[Note: Select one or more answer choices]