Question:
In Young's double slit experiment, one of the slits is wider than the other, so that the amplitude of light from one slit is double of that from the other slit. If Im is the maximum intensity, what is the resultant intensity when they interfere at phase difference Q?
In Young's double slit experiment, one of the slits is wider than the other, so that the amplitude of light from one slit is double of that from the other slit. If Im is the maximum intensity, what is the resultant intensity when they interfere at phase difference Q?
Updated On: Sep 15, 2024
- \(\frac{I_m}{9}(1-8cos^2\frac{Q}{2})\)
- \(\frac{I_m}{9}(1+8cos^2\frac{Q}{2})\)
- \(\frac{I_m}{9}(1-8cos^2Q)\)
- \(\frac{I_m}{9}(1+sin^2\frac{Q}{2})\)
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The Correct Option is B
Solution and Explanation
The correct option is (B) : \(\frac{I_m}{9}(1+8cos^2\frac{Q}{2})\)
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