Question

In winding, if traverse speed and package surface speed are the same, the angle of wind (in degree) is \(\underline{\hspace{2cm}}\).

Hint:

When the traverse speed and package surface speed are equal, the angle of wind is always \( 45^\circ \).

Answer 1

Correct Answer: 45

The angle of wind \( \theta \) is given by: \[ \tan(\theta) = \frac{\text{Traverse Speed}}{\text{Package Surface Speed}}. \] Since the traverse speed and package surface speed are the same, we have: \[ \tan(\theta) = 1. \] Thus, \( \theta = 45^\circ \). Thus, the angle of wind is \( 45^\circ \).