In which of the following year India had a surplus in its current account?
Show Hint
- 2018-19
- 2019-20
- 2020-21
- 2021-22
The Correct Option is C
Solution and Explanation
Step 1: Understanding India's current account surplus.
India experienced a surplus in its current account in the year 2020-21, mainly due to reduced imports during the COVID-19 pandemic and increased remittances. This was a rare event as India typically runs a current account deficit.
Step 2: Analysis of options.
- (A) 2018-19: India had a deficit in the current account in this year.
- (B) 2019-20: India had a deficit in the current account in this year.
- (C) 2020-21: This is correct. India had a surplus in its current account during this year.
- (D) 2021-22: India had a deficit in the current account in this year.
Step 3: Conclusion.
The correct answer is (C), as India had a surplus in its current account in the year 2020-21.
Top Questions on International Trade
- Expenditure towards the maintenance of embassies and diplomatic missions are included in which of the following accounts of the balance of payments.
- CUET (PG) - 2025
- Economics
- International Trade
Case for Free Trade
The act of opening up economies for trading is known as free trade or trade liberalization. This is done by bringing down trade barriers like tariffs. Trade liberalization allows goods and services from everywhere to compete with domestic products and services.
Globalisation along with free trade can adversely affect the economies of developing countries by not giving equal playing field by imposing conditions which are unfavorable. With the development of transport and communication systems goods and services can travel faster and farther than ever before. But free trade should not only let rich countries enter the markets, but allow the developed countries to keep their own markets protected from foreign products.
Countries also need to be cautious about dumped goods; as along with free trade dumped goods of cheaper prices can harm the domestic producers.
Explain the meaning of ‘trade liberalisation’.
- CBSE CLASS XII - 2025
- Geography
- International Trade
- Explain the factors affecting trade.
- Maharashtra Class XII - 2025
- Geography
- International Trade
Case for Free Trade
The act of opening up economies for trading is known as free trade or trade liberalisation. This is done by bringing down trade barriers like tariffs. Trade liberalisation allows goods and services from everywhere to compete with domestic products and services.
Globalisation along with free trade can adversely affect the economies of developing countries by not giving equal playing field by imposing conditions which are unfavourable. With the development of transport and communication systems, goods and services can travel faster and farther than ever before. But free trade should not only let rich countries enter the markets, but allow the developed countries to keep their own markets protected from foreign products.
Countries also need to be cautious about dumped goods; as along with free trade dumped goods of cheaper prices can harm the domestic producers.- CBSE CLASS XII - 2025
- Geography
- International Trade
- Explain the changing pattern of the composition of India’s exports.
- CBSE CLASS XII - 2025
- Geography
- International Trade
Questions Asked in CUET PG exam
- Match List-I with List-II:
\[ \begin{array}{|l|l|} \hline \textbf{List-I (Equation)} & \textbf{List-II (Roots)} \\ \hline (A)\; (z + 1)^{2n} + (z - 1)^{2n} = 0 & (I)\; \cos\!\left(\tfrac{\pi}{5}\right) \pm i\sin\!\left(\tfrac{\pi}{5}\right), -1, \cos\!\left(\tfrac{3\pi}{5}\right) \pm i\sin\!\left(\tfrac{3\pi}{5}\right) \\ \hline (B)\; z^5 + z^4 + z^3 + z^2 + z + 1 = 0 & (II)\; \text{purely imaginary number} \\ \hline (C)\; (z-1)^5 + z^5 = 0 & (III)\; -1,\; \pm\frac{1}{2} \pm i\frac{\sqrt{3}}{2} \\ \hline (D)\; z^5 + 1 = 0 & (IV)\; \tfrac{1}{2}\left[1+i\cot\!\left(\tfrac{p\pi}{10}\right)\right], \; p = 1,3,5,7,9 \\ \hline \end{array} \]
Choose the correct answer from the options given below:- CUET (PG) - 2025
- Complex numbers
- Which of the following statements are correct?
If \[ A = \begin{pmatrix} p & q \\ 0 & 1 \end{pmatrix}, \quad B = \begin{pmatrix} 1 & q \\ 0 & 1 \end{pmatrix}, \] then
(A) \[ B^n = \begin{pmatrix} 1 & nq \\ 0 & 1 \end{pmatrix} \]
(B) \[ A^n = \begin{pmatrix} p^n & q\frac{p^n-1}{p-1} \\ 0 & 1 \end{pmatrix}, \; \text{if } p \neq 1 \]
(C) \[ AB = \begin{pmatrix} p & pq+q \\ 0 & 1 \end{pmatrix} \]
(D) \[ B^{n-1} = \begin{pmatrix} 1 & (n+1)q \\ 0 & 1 \end{pmatrix} \]
(E) \[ AB^n = \begin{pmatrix} p & (np+1)q \\ 0 & 1 \end{pmatrix} \]
Choose the correct answer from the options given below:- CUET (PG) - 2025
- Linear Algebra
- If the matrix \[ A = \begin{pmatrix} 2 & 0 & -1 \\ 5 & 1 & 0 \\ 0 & 1 & 3 \end{pmatrix} \] satisfies the matrix equation:
- CUET (PG) - 2025
- Linear Algebra
- If the rank of matrix \[ \begin{pmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 0 & 7 & \lambda \end{pmatrix} \] is 2, then the value of \(\lambda\) is:
- CUET (PG) - 2025
- Linear Algebra
- Match List-I with List-II
\[ \begin{array}{|l|l|} \hline \textbf{List-I} & \textbf{List-II} \\ \hline (A) \; \lim_{x \to 0} \frac{\ln(1+x)}{\sin x} & (I) \; 1 \\ (B) \; \lim_{x \to \infty} 2x \tan\left(\tfrac{1}{x}\right) & (II) \; 0 \\ (C) \; \lim_{x \to \infty} \frac{x^2}{e^x} & (III) \; 2 \\ (D) \; \lim_{x \to 1} x^{\tfrac{1}{x-1}} & (IV) \; e \\ \hline \end{array} \]
Choose the correct answer from the options given below:
- CUET (PG) - 2025
- Calculus