In which of the following pairs are both the ions coloured in aqueous solution? (Atomic number: Sc = 21, Ti = 22, Ni = 28, Cu = 29, Co = 27)
Ni2+, Ti3+
Sc3+, Ti3+
Sc3+, Co2+
Ni2+, Cu+
The Correct Option is A
Solution and Explanation
28Ni = 1s2 2s2 2p6 3s2 3p6 3d8 4s2
Ni2+=1s2 2s2 2p6 3s2 3p6 3d8
22Ti = 1s2 2s2 2p6 3s2 3p6 3d2 4s2
Ti3+=1s2 2s2 2p6 3s2 3p6 3d1
Ni2+ and Ti3+ ions are coloured ions in aqueous solution due to the presence of unpaired electrons d − subshell.
So, the correct option is (A): Ni2+, Ti3+
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Concepts Used:
D and F Block Elements
The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements.
They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.
Read More: The d and f block elements