Comprehension

In the year 2012, 17 lakh tonne of a vegetable was produced in a certain State. Its production status in six Districts of that State is shown in pie chart 1. The percentages of total expenditure incurred under different heads for producing this vegetable in any district is shown in pie chart II.
 Production status in six Districts of that State is shown in pie chart 1.
The percentages of total expenditure incurred under different heads for producing this vegetable in any district
                                         Pie Chart II

Question: 1

The monthly expenses for water in district B is more/less than the monthly expenditure for electricity in District A by ....... (the total expenditure is ₹1700 per tonne in a year).

Updated On: Sep 23, 2024
  • ₹ 82167 less
  • ₹ 82167 more
  • ₹ 986000 less
  • ₹ 1003000 less
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The Correct Option is C

Solution and Explanation

Monthly expenses for water in district \(B = \frac{17}{100} \times 2.56\)
= 435200
Monthly expenditure for electricity in District \(A = \frac{14}{100} \times 3.15\)
= 441000
Difference \(= (441000-435200)\)
\(= 58000\)
Expenditure \(58000\times1700\)
\(= ₹\ 986000\)
So the correct option is (C)
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Question: 2

The total expenditure per tonne production of vegetable in these districts is ₹ 5580. The amount spent towards transport in district F is more/less than that in district E by

Updated On: Sep 23, 2024
  • more by ₹ 11085600
  • less by ₹ 11085600
  • more by ₹ 72540000
  • less by ₹ 72540000
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The Correct Option is C

Solution and Explanation

F = 1.88
E = 1.75
Total expenses for \(F = 1.88\times5580\)
= 10490.4
Total expenses for \(E = 1.75\times5580\)
= 9765
Difference \(= 10490.4–9765\)
= 725.4 lakh
So the correct option is (C)
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Question: 3

If the expenditure incurred in district D is 20% more than that in district B and ₹ 950000 were spent in district B, then expenses for labour in district D are

Updated On: Sep 23, 2024
  • ₹ 1140000
  • ₹ 152000
  • ₹ 228000
  • ₹ 190000
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The Correct Option is C

Solution and Explanation

Expenditure incurred in district D is 20\(\%\) more than that in district B and ₹ 950000 were spent in district B, then expenses for labour in
district D :
Expenditure incurred in district D = \(D = 1.2\times950000\)
= 1140000
Expenses for labour in district D = 20\(\%\)of total expenditure
\(\frac{20}{100}\times1140000\)
= 228000.
So the correct option is (C)
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Question: 4

The profit earned by the sale of the vegetable in district F is 25%. The sale price being ₹10000 per tonne, how much money was spent on fertilizers?

Updated On: Sep 23, 2024
  • ₹ 8.46 crore
  • ₹ 33.84 crore
  • ₹ 33840
  • ₹ 2707200000
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The Correct Option is D

Solution and Explanation

The profit earned by the sale of the vegetable in district F is 25\(\%\). The sale price being ₹10000 per tonne, then money was spent on
fertilizers:
Total selling price in district \(F = 1.88 \times 10,000 = 18,800 \times 10^6\)
S.P. = (1+P\(\%\))\(\times\)C.P (C.P. = cost price)
\(\text{C.P.} = \frac{100}{125} \times 18800 \times 10^6\)
\(\text{C.P.} = 150.4 \times 10^8\)
Money was spent on Fertilizers = 18\(\%\) of CP
\(0.18 \times 150.4 \times 10^8\)
\(= 27.072 \times 10^8\)
\(= ₹ 2707200000\)
So the correct option is (D)
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Question: 5

The profit earned by the sale of the vegetable in district F is 25%. The sale price being ₹ 10000 per tonne, how much money was spent on fertilizers?

Updated On: Sep 23, 2024
  • 38 crore
  • 27.2 crore
  • 25 crore
  • 33.875 crore
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The Correct Option is B

Solution and Explanation

The profit earned by the sale of the vegetable in district F is 25\(\%\). The sale price being ₹10000 per tonne, then money was spent on
fertilizers:
Total selling price in district F = \(1.88 \times 10000 = 18800 \times 10^6\)
S.P. = (1+P\(\%\))\(\times\)C.P (C.P. = cost price)

\(\text{C.P.} = \frac{100}{125} \times 18800 \times 10^6\)

\(\text{C.P.} = 150.4 \times 10^8\)
Money was spent on Fertilizers = 18\(\%\) of CP
\(0.18 \times 150.4 \times 10^8\)
\(=0.18 \times 150.4 \times 10^8 = 27.072 \times 10^8\)
\(= 27.2\) crore.

So the correct option is (B)

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