Question

In the summer of 2012, in New Delhi, the mean temperature of Monday to Wednesday was 41° C and of Tuesday to Thursday was 43°C If the temperature on Thursday was 15% higher than that of Monday, then the temperature in °C on Thursday was

• A. 40
• B. 43
• C. 46
• D. 49

Answer 1

The Correct Option is C

To find the temperature on Thursday, we start by setting up equations based on the given information. Let the temperature on Monday be \( M \), on Tuesday be \( T \), on Wednesday be \( W \), and on Thursday be \( H \).

We have two equations from the given data:

1. \(\frac{M + T + W}{3} = 41\)

\(\Rightarrow M + T + W = 123\) (Equation 1)

2. \(\frac{T + W + H}{3} = 43\)

\(\Rightarrow T + W + H = 129\) (Equation 2)

Additionally, we are told the temperature on Thursday was 15% higher than that of Monday:

\( H = M + 0.15M = 1.15M \) (Equation 3)

Substituting Equation 3 in Equation 2, we get:

\( T + W + 1.15M = 129 \)

From Equation 1, \( T + W = 123 - M \). Substituting this into the equation above gives:

\( 123 - M + 1.15M = 129 \)

\( 123 + 0.15M = 129 \)

Solving for \( M \):

\( 0.15M = 129 - 123 \)

\( 0.15M = 6 \)

\( M = \frac{6}{0.15} = 40 \)

Now, substituting the value of \( M \) back in Equation 3 to find \( H \):

\( H = 1.15 \times 40 = 46 \)

Therefore, the temperature on Thursday was 46°C.