Question

In the reaction

‘Q’ is :

• A. C₆H₅N₂Cl
• B. ortho-hydroxyazobenzene
• C. para-hydroxyazobenzene
• D. meta-hydroxyazobenzene

Answer 1

The Correct Option is C

The reaction sequence involves two main steps:

• Diazotization: Aniline reacts with NaNO₂ in the presence of dilute HCl to form the diazonium salt (Ph-N₂⁺).
• Coupling reaction: The diazonium salt reacts with phenol in the presence of NaOH, leading to the formation of an azo compound.

In this case, the coupling between the diazonium salt and phenol occurs at the para position due to the activating effect of the hydroxyl group on the phenol ring.

Thus, the product Q is para-hydroxyazobenzene, corresponding to option (C).

Answer 2

- In the first step, aniline reacts with sodium nitrite (NaNO₂) in dilute HCl to form a diazonium salt (C₆H₅N₂Cl).
In the second step, phenol reacts with the diazonium salt in the presence of NaOH to form para-hydroxyazobenzene. Thus, Q is para-hydroxyazobenzene.