In the given reaction sequence, the steps can be broken down as follows:
The starting compound has an amine group (NH₂) attached to a benzene ring.
In the first step, the amine group undergoes diazotization, where it reacts with NaNO₂ and dilute HCl to form the diazonium salt (P).
In the second step, the diazonium salt reacts with BF₃, leading to the formation of Q.
In the third step, the diazonium compound (Q) is reacted with Cu and NaNO₂, resulting in the formation of R, which is a nitro group (NO₂) attached to the benzene ring.
The correct sequence of reactions corresponds to Option C:
P is the diazonium salt formed with NaNO₂ and dilute HCl.
Q is the intermediate after reacting with BF₃.
R is the final product after reacting with Cu and NaNO₂, which is a nitrobenzene.
Thus, the answer is Option C.
List-I | List-II | ||
(A) | [Co(NH3)5(NO2)]Cl2 | (I) | Solvate isomerism |
(B) | [Co(NH3)5(SO4)]Br | (II) | Linkage isomerism |
(C) | [Co(NH3)6] [Cr(CN)6] | (III) | Ionization isomerism |
(D) | [Co(H2O)6]Cl3 | (IV) | Coordination isomerism |
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |