Question:

In the magnetic meridian of a certain place the horizontal component of earth?? magnetic field is 0.25 G and dip angle is $60^?$. The magnetic field of the earth at this location is

Updated On: Jun 23, 2023
  • 0.50 G
  • 0.52 G
  • 0.54 G
  • 0.56 G
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Here, $H_E = 0.25\, G$ and $cos\,?$ $=\frac{H_{E}}{B_{E}}$ $\therefore$ The magnetic field of earth at the given location is $B_{E}=\frac{H_{E}}{cos\,60^{?}}=\frac{0.25}{1 / 2}=0.50\,G$
Was this answer helpful?
0
0

Top Questions on Magnetism and matter

View More Questions

Notes on Magnetism and matter

Concepts Used:

Magnetism & Matter

Magnets are used in many devices like electric bells, telephones, radio, loudspeakers, motors, fans, screwdrivers, lifting heavy iron loads, super-fast trains, especially in foreign countries, refrigerators, etc.

Magnetite is the world’s first magnet. This is also called a natural magnet.  Though magnets occur naturally, we can also impart magnetic properties to a substance. It would be an artificial magnet in that case.

Read More: Magnetism and Matter

Some of the properties of the magnetic field lines are:

  • The lines and continuous and outside the magnet, the field lines originate from the North pole and terminate at the South pole
  • They form closed loops traversing inside the magnet. 
  • But here the lines seem to originate from the South pole and terminate at the North pole to form closed loops.
  • More number of close lines indicate a stronger magnetic field
  • The lines do not intersect each other
  • The tangent drawn at the field line gives the direction of the field at that point.