Question:

In the Langmuir Isotherm, following statements are true except one

Updated On: Nov 12, 2025
  • Adsorbed layer is uniform all over adsorbent
  • No desorption takes place when the gas strikes solid surface
  • No interaction between the adjacent adsorbed molecules takes place
  • The layer of the gas adsorbed on the solid adsorbent is one molecule thick
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

The Langmuir Isotherm is a model that describes the adsorption of molecules onto a solid surface. It assumes that:

  • The surface contains a finite number of identical sites where adsorption can occur.
  • Each site can accommodate only a single molecule, meaning the layer of adsorbed gas is one molecule thick.
  • Adsorbed molecules do not interact with each other.
  • The adsorbed layer is uniform all over the adsorbent surface.

Let us analyze each option provided in relation to these assumptions:

  1. Adsorbed layer is uniform all over adsorbent: This aligns with the Langmuir Isotherm, which assumes a homogeneous surface where each site is equivalent.
  2. No desorption takes place when the gas strikes solid surface: This statement is incorrect. The Langmuir Isotherm considers a dynamic equilibrium between adsorption and desorption. When a gas molecule strikes the surface, it can adsorb or desorb based on this equilibrium.
  3. No interaction between the adjacent adsorbed molecules takes place: The Langmuir model assumes non-interacting adsorbed molecules, making this statement true according to the model.
  4. The layer of the gas adsorbed on the solid adsorbent is one molecule thick: This is a basic assumption of the Langmuir Isotherm, thus this statement is true.

Therefore, the statement that is not true according to the Langmuir Isotherm is: No desorption takes place when the gas strikes solid surface. This contradicts the dynamic nature of adsorption and desorption in the model.

Was this answer helpful?
0
0

Top Questions on Thermodynamics

View More Questions