Question:

In the indicator diagram fig. shown of Carnot cycle Ta, Tb, Te, Td represent temperature of gas at A, B, C, D respectively. Which of the following is correct relation

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Carnot: temperatures equal on each isothermal branch.
Updated On: Jan 9, 2026
  • \(T_a=T_b=T_c=T_d\)
  • \(T_a=T_c,\;T_b=T_d\)
  • \(T_a=T_d,\;T_c=T_b\)
  • \(T_a=T_b,\;T_c=T_d\)
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The Correct Option is D

Solution and Explanation

Step 1: Carnot cycle has two isotherms and two adiabats.
Step 2: Points on same isotherm have same temperature.
Step 3: From diagram A→B is isothermal; C→D is other isothermal.
Step 4: Therefore: \[ T_a=T_b,\qquad T_c=T_d. \] Hence → (D).
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