Question

In the given logic circuit, if A and B are the inputs, then P and Q are respectively
\

• A. \((A + B),\quad (P \cdot A)\)
• B. \((A \cdot B),\quad (P \cdot B)\)
• C. \((A + B),\quad (P + B)\)
• D. \((A + B),\quad B\)

Hint:

OR gate output is \(A + B\); AND gate with one input \(A + B\), the other \(B\) gives \(Q = B\).

Answer 1

The Correct Option is D

From the logic diagram:
- The first gate is an OR gate: \[ P = A + B \] - P is connected to one input of the AND gate, and B is directly connected to the other input.
So, \[ Q = P \cdot B = (A + B) \cdot B \Rightarrow Q = B \] (Since \(A + B\) AND \(B\) simplifies to just \(B\))
Thus:
- \(P = A + B\)
- \(Q = B\)

Answer 2

The logic circuit consists of the following:

• The first gate is an OR gate that takes inputs \( A \) and \( B \).
• The output of the OR gate is \( P \), so \( P = A + B \).
• This output \( P \) and the original input \( B \) are then fed into an AND gate.
• So, the final output \( Q = P \cdot B = (A + B) \cdot B \).

However, based on the diagram and asked values for \( P \) and \( Q \), they are:

Correct Answer:
\[ P = A + B,\quad Q = B \] since the output line from the OR gate marked as \( P \) is correct, but \( Q \) is directly connected only to \( B \) (as shown in the circuit). The OR gate output doesn't contribute to Q in this particular figure due to how the wiring is done.

Final Answer:
\((A + B),\quad B\)